2(x^2+3x+2)-(2x^2+3x-7)=17

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Solution for 2(x^2+3x+2)-(2x^2+3x-7)=17 equation: 


Simplifying
2(x2 + 3x + 2) + -1(2x2 + 3x + -7) = 17

Reorder the terms:
2(2 + 3x + x2) + -1(2x2 + 3x + -7) = 17
(2 * 2 + 3x * 2 + x2 * 2) + -1(2x2 + 3x + -7) = 17
(4 + 6x + 2x2) + -1(2x2 + 3x + -7) = 17

Reorder the terms:
4 + 6x + 2x2 + -1(-7 + 3x + 2x2) = 17
4 + 6x + 2x2 + (-7 * -1 + 3x * -1 + 2x2 * -1) = 17
4 + 6x + 2x2 + (7 + -3x + -2x2) = 17

Reorder the terms:
4 + 7 + 6x + -3x + 2x2 + -2x2 = 17

Combine like terms: 4 + 7 = 11
11 + 6x + -3x + 2x2 + -2x2 = 17

Combine like terms: 6x + -3x = 3x
11 + 3x + 2x2 + -2x2 = 17

Combine like terms: 2x2 + -2x2 = 0
11 + 3x + 0 = 17
11 + 3x = 17

Solving
11 + 3x = 17

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 3x = 17 + -11

Combine like terms: 11 + -11 = 0
0 + 3x = 17 + -11
3x = 17 + -11

Combine like terms: 17 + -11 = 6
3x = 6

Divide each side by '3'.
x = 2

Simplifying
x = 2

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